Among NO_3^{-} (I),AsO_3^{3-} (II),CO_3^{2-} | vedclass

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(A) To determine the geometry,we calculate the hybridization of the central atom using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the

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$II, IV, V$

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(A) To determine the geometry,we calculate the hybridization of the central atom using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.SpeciesHybridizationGeometry$NO_3^{-}$$sp^2$Trigonal planar (Planar)$AsO_3^{3-}$$sp^3$Pyramidal (Non-planar)$CO_3^{2-}$$sp^2$Trigonal planar (Planar)$ClO_3^{-}$$sp^3$Pyramidal (Non-planar)$SO_3^{2-}$$sp^3$Pyramidal (Non-planar)Thus,the non-planar species are $AsO_3^{3-} (II)$,$ClO_3^{-} (IV)$,and $SO_3^{2-} (V)$.

List-$I$	List-$II$
$(A)$ $PCl_3$	$(I)$ Square planar
$(B)$ $BF_3$	$(II)$ $T$-shape
$(C)$ $ClF_3$	$(III)$ Trigonal pyramidal
$(D)$ $XeF_4$	$(IV)$ See-saw
	$(V)$ Trigonal planar

Among $NO_3^{-} (I)$,$AsO_3^{3-} (II)$,$CO_3^{2-} (III)$,$ClO_3^{-} (IV)$,and $SO_3^{2-} (V)$,the non-planar species are:

Similar Questions

The correct order of bond angle is

Match the molecules in List-$I$ with their correct geometries in List-$II$ according to $VSEPR$ theory:
List-$I$ List-$II$
$(A)$ $PCl_3$ $(I)$ Square planar
$(B)$ $BF_3$ $(II)$ $T$-shape
$(C)$ $ClF_3$ $(III)$ Trigonal pyramidal
$(D)$ $XeF_4$ $(IV)$ See-saw
$(V)$ Trigonal planar

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